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Old 01-10-2019, 07:55 AM   #1
Johndeeretech
 
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P-Pump timing question

just seeing if anybody would know off the top of there head what the timing retardation would be degree wise on pump timing for a engine that has a .20 over head gasket installed without the head or block being decked (stock)
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Old 01-10-2019, 09:06 AM   #2
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I guess my question is how many degrees of timing does your engine get retarded by if you use a .20 over head gasket moving the head away from the top of the piston at TDC by .20
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Old 01-10-2019, 09:45 AM   #3
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1 degree of crank rotation equals .026" of piston travel

Assuming its a 5.9 crank
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Old 01-10-2019, 10:45 AM   #4
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Quote:
Originally Posted by BluegrassDiesel View Post
1 degree of crank rotation equals .026" of piston travel

Assuming its a 5.9 crank


Going off of this, you would retard 3/4 of a degree? Right? My math is lacking this morning


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Old 01-10-2019, 10:47 AM   #5
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Quote:
Originally Posted by BluegrassDiesel View Post
1 degree of crank rotation equals .026" of piston travel

Assuming its a 5.9 crank
Awesome, Thank you that is exactly the info I needed and yes it does have a stock 5.9 crank
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Old 01-10-2019, 03:42 PM   #6
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Quote:
Originally Posted by BluegrassDiesel View Post
1 degree of crank rotation equals .026" of piston travel

Assuming its a 5.9 crank
How did you come up with this?
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Old 01-11-2019, 08:04 AM   #7
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4.72” stroke divided by 180 degrees
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Old 01-11-2019, 02:35 PM   #8
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Originally Posted by BluegrassDiesel View Post
4.72 stroke divided by 180 degrees
Not how it works. Piston speeds follow through a sinusoidal wave, peak speed at around 75 degrees BTDC/ATDC (in this given example, depends on rod length), obviously coming to a stop and reversing at TDC and BDC.

Peak piston movement per degree rotation is 1.097mm (0.043")@74 degrees BTDC
0.5mm (0.020") away from TDC would be at ~6.5 degrees BTDC.
0.66mm (0.026") per degree takes place around 30 degrees BTDC and 128 degrees BTDC.
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Old 01-11-2019, 05:34 PM   #9
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If I am understanding the question correctly, then it all depends on what timing you are starting at... So lets say you start at 13.5 BTDC. If I have my values correct, that should put the piston .063" below deck height assuming 4.724 stroke, 7.559 rod, 2.817 piston pin height, and 12.716 deck height. You are wanting to retard the timing to account for an extra .020" over head gasket so you want the piston to be .020" higher in the bore before injection? So that would mean you would need to set timing at 11.803 BTDC.
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Old 01-11-2019, 05:38 PM   #10
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Your question is still kind of weird to me though. I don't get what you are trying to accomplish or why? You don't "lose timing" because you put on a thicker head gasket. You lose compression and your injection event will be focused on a slightly different area of the piston (possibly even out of the bowl depending on set timing and injector angle). But your injection event still happens at the same time....
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