I've watched some of the PDD videos and have been attempting to get a rough estimate of the power my truck is capable of running a single SXE369.
My assumptions are 7whp per lb air/minute.
4000 RPM
4000rpm x 179.5 cubic in/revolution = 718000 / 1728 = 415 CFM x .75 (estimated mechanical efficiency) = 311.6 cubic ft/min
5K Ft elevation = 12.4 PSI atmosphere
4.2 pressure ratio x 12.4 = 52.08 true pressure - 12.4 = 39.68 gauge pressure, will round up to 40 just to be simple.
http://www.full-race.com/store/image...-content-6.jpg <--- turbo
map for SXE369
4.2 PR to approx 85 lbs/min of air has an efficiency of approx .7 according to
map.
4.2pr x .7 efficiency = 2.94 density ratio
2.94 density ratio x 21.5 lb min engine is producing at 4000 rpm = 63.21 lb/min x 1.45 (stock intercooler efficiency estimate) = 91.65 lb/min x 7 = 641.58 whp.
I'm a little confused on calculating efficiency number from turbo
map and 641 whp seems quite high for my truck but I don't have a dyno or race track nearby to test it out.
Is my math off or am I missing something?
Thanks,
Andrew