Tim, I thought the nozzle size was related to the injectors. Maybe I am the one that is confused. My basic point is that a certain injector has a limit to the HP it can produce. If HUEI injectors are limited to the injector hold volume, then the only thing that can vary is the extent of combustion (as you were saying Tim). If there is haze or smoke, it is not 100% efficiently combusted.
Stepping back, we know that stock injectors with as much NOS as possible maxes out around 480RWHP. That's what I am told, and it sounds about right since we know the stock turbo is more than enough to basically clean up the stock sticks, but we also know that air is not as good of an oxidizer as nitrous, so a little bump from the 430RWHP to 480RWHP by adding nitrous to an otherwise stock truck (assume tune and pipe) sounds about right. That is, I will take it as fact that nitrous with the stock sticks will yield very close to 100% combustion efficiency.
So, if we take the ratio of 200/135, we have 1.48. That means that if we could combust just as efficiently with these larger injectors (which usually you can't, but if you could), a set of 200's should yield as much as 711RWHP. The 691RWHP level works to about 97.2% combustion efficiency, which is believable. On a side note, 190's works to 675RWHP with the same approach, which is why I called BS on the 755RWHP claim. And that 675 number assumes 100% efficiency, which they will not have as you will see below. I still say BS.
As you stuff more fuel into the chamber, it becomes harder and harder to burn it all. That is just physics. We should expect a slow, but steady decrease in combustion efficiency as we go to larger and larger injectors. We can estimate the loss in efficiency, if we assume it is linear for the injector sizes we have data for. That is, let's assume that stock sticks (135 mm^3 per stroke) gives 480RWHP and call that 100% combustion efficiency, and that 200's yields 691RWHP. We can create a simple equation as follows:
Burn Efficiency = 105.8154 - (Injector Size in mm^3/stroke)*0.04308
Sorry, this is the engineer in me coming out. But it makes sense. If we apply this formula, we can predict what the maximum RWHP will be for various injector sizes:
nozzle efficiency RWHP
135 100 480
160 98.9 563
185 97.8 644
190 97.6 660
200 97.2 691.2
225 96.1 769
275 94.0 919
345 91.0 1116
430 87.3 1335
Now all of this assumes the efficiency loss is linear. It probably is not, but it is a start and the numbers are not that crazy. This formula already takes into account drive train losses, so I think it should be ok unless those change in percentage.
Thoughts?
Ralph